41341210000033 has 2 divisors, whose sum is σ = 41341210000034. Its totient is φ = 41341210000032.

The previous prime is 41341209999997. The next prime is 41341210000073. The reversal of 41341210000033 is 33000001214314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38708953609104 + 2632256390929 = 6221652^2 + 1622423^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-41341210000033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 41341209999959 and 41341210000013.

It is not a weakly prime, because it can be changed into another prime (41341210000073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20670605000016 + 20670605000017.

It is an arithmetic number, because the mean of its divisors is an integer number (20670605000017).

Almost surely, 2^{41341210000033} is an apocalyptic number.

It is an amenable number.

41341210000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

41341210000033 is an equidigital number, since it uses as much as digits as its factorization.

41341210000033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 41341210000033 its reverse (33000001214314), we get a palindrome (74341211214347).

The spelling of 41341210000033 in words is "forty-one trillion, three hundred forty-one billion, two hundred ten million, thirty-three", and thus it is an aban number.