Base | Representation |
---|---|
bin | 1100000010000110000… |
… | …01011100001011010001 |
3 | 1110112011102202201221111 |
4 | 12001003001130023101 |
5 | 23233211433431231 |
6 | 513533214053321 |
7 | 41604314106634 |
oct | 6010301341321 |
9 | 1415142681844 |
10 | 413441311441 |
11 | 14a380929654 |
12 | 681647aa241 |
13 | 2ccab287072 |
14 | 160213a7c1b |
15 | ab4b96e4b1 |
hex | 604305c2d1 |
413441311441 has 4 divisors (see below), whose sum is σ = 413491537252. Its totient is φ = 413391085632.
The previous prime is 413441311429. The next prime is 413441311453. The reversal of 413441311441 is 144113144314.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 144113144314 = 2 ⋅72056572157.
It is an interprime number because it is at equal distance from previous prime (413441311429) and next prime (413441311453).
It can be written as a sum of positive squares in 2 ways, for example, as 186416697600 + 227024613841 = 431760^2 + 476471^2 .
It is a cyclic number.
It is not a de Polignac number, because 413441311441 - 27 = 413441311313 is a prime.
It is a super-3 number, since 3×4134413114413 (a number of 36 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (413441311471) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25100556 + ... + 25117021.
It is an arithmetic number, because the mean of its divisors is an integer number (103372884313).
Almost surely, 2413441311441 is an apocalyptic number.
It is an amenable number.
413441311441 is a deficient number, since it is larger than the sum of its proper divisors (50225811).
413441311441 is an equidigital number, since it uses as much as digits as its factorization.
413441311441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50225810.
The product of its digits is 9216, while the sum is 31.
Adding to 413441311441 its reverse (144113144314), we get a palindrome (557554455755).
The spelling of 413441311441 in words is "four hundred thirteen billion, four hundred forty-one million, three hundred eleven thousand, four hundred forty-one".
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