Base | Representation |
---|---|
bin | 111100001010011111001… |
… | …110110100100101011001 |
3 | 112122020200112110100011111 |
4 | 330022133032310211121 |
5 | 1020214303040021442 |
6 | 12443155251300321 |
7 | 604463013111535 |
oct | 74123716644531 |
9 | 15566615410144 |
10 | 4134430001497 |
11 | 1354446a51464 |
12 | 5693442aa6a1 |
13 | 23cb4b708b13 |
14 | 104170cd2bc5 |
15 | 7282cbd1b17 |
hex | 3c29f3b4959 |
4134430001497 has 2 divisors, whose sum is σ = 4134430001498. Its totient is φ = 4134430001496.
The previous prime is 4134430001411. The next prime is 4134430001503. The reversal of 4134430001497 is 7941000344314.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3798799800601 + 335630200896 = 1949051^2 + 579336^2 .
It is a cyclic number.
It is not a de Polignac number, because 4134430001497 - 215 = 4134429968729 is a prime.
It is a super-2 number, since 2×41344300014972 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4134430031497) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2067215000748 + 2067215000749.
It is an arithmetic number, because the mean of its divisors is an integer number (2067215000749).
Almost surely, 24134430001497 is an apocalyptic number.
It is an amenable number.
4134430001497 is a deficient number, since it is larger than the sum of its proper divisors (1).
4134430001497 is an equidigital number, since it uses as much as digits as its factorization.
4134430001497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 145152, while the sum is 40.
The spelling of 4134430001497 in words is "four trillion, one hundred thirty-four billion, four hundred thirty million, one thousand, four hundred ninety-seven".
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