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41371231204153 is a prime number
BaseRepresentation
bin10010110100000011111011…
…00010100011001100111001
312102111001101020100120000001
421122001331202203030321
520410311240142013103
6223553403051513001
711466654451005304
oct1132017542431471
9172431336316001
1041371231204153
1112200493518224
124782031758761
131a113a0c07ac6
14a30541dadb3b
154bb2623a401d
hex25a07d8a3339

41371231204153 has 2 divisors, whose sum is σ = 41371231204154. Its totient is φ = 41371231204152.

The previous prime is 41371231204097. The next prime is 41371231204211. The reversal of 41371231204153 is 35140213217314.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37883495671849 + 3487735532304 = 6154957^2 + 1867548^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-41371231204153 is a prime.

It is not a weakly prime, because it can be changed into another prime (41371231214153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20685615602076 + 20685615602077.

It is an arithmetic number, because the mean of its divisors is an integer number (20685615602077).

Almost surely, 241371231204153 is an apocalyptic number.

It is an amenable number.

41371231204153 is a deficient number, since it is larger than the sum of its proper divisors (1).

41371231204153 is an equidigital number, since it uses as much as digits as its factorization.

41371231204153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 37.

The spelling of 41371231204153 in words is "forty-one trillion, three hundred seventy-one billion, two hundred thirty-one million, two hundred four thousand, one hundred fifty-three".