Base | Representation |
---|---|
bin | 10010110100010100100110… |
… | …11010011011011000011001 |
3 | 12102111220111110100102122011 |
4 | 21122022103122123120121 |
5 | 20410433111123431223 |
6 | 224001443533225521 |
7 | 11500422431305435 |
oct | 1132122332333031 |
9 | 172456443312564 |
10 | 41380188108313 |
11 | 1220426a45395a |
12 | 47839113322a1 |
13 | 1a1219a7793b2 |
14 | a30b517a79c5 |
15 | 4bb5d88bb80d |
hex | 25a29369b619 |
41380188108313 has 2 divisors, whose sum is σ = 41380188108314. Its totient is φ = 41380188108312.
The previous prime is 41380188108307. The next prime is 41380188108401. The reversal of 41380188108313 is 31380188108314.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 23175058146304 + 18205129962009 = 4814048^2 + 4266747^2 .
It is a cyclic number.
It is not a de Polignac number, because 41380188108313 - 217 = 41380187977241 is a prime.
It is not a weakly prime, because it can be changed into another prime (41380158108313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20690094054156 + 20690094054157.
It is an arithmetic number, because the mean of its divisors is an integer number (20690094054157).
Almost surely, 241380188108313 is an apocalyptic number.
It is an amenable number.
41380188108313 is a deficient number, since it is larger than the sum of its proper divisors (1).
41380188108313 is an equidigital number, since it uses as much as digits as its factorization.
41380188108313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 442368, while the sum is 49.
Subtracting from 41380188108313 its reverse (31380188108314), we obtain a palindrome (9999999999999).
The spelling of 41380188108313 in words is "forty-one trillion, three hundred eighty billion, one hundred eighty-eight million, one hundred eight thousand, three hundred thirteen".
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