4140003321341 has 4 divisors (see below), whose sum is σ = 4150431541692. Its totient is φ = 4129575100992.

The previous prime is 4140003321317. The next prime is 4140003321343. The reversal of 4140003321341 is 1431233000414.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 918427055716 + 3221576265625 = 958346^2 + 1794875^2 .

It is a cyclic number.

It is not a de Polignac number, because 4140003321341 - 2⁶ = 4140003321277 is a prime.

It is a super-2 number, since 2×4140003321341² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4140003321341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4140003321343) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5214109580 + ... + 5214110373.

It is an arithmetic number, because the mean of its divisors is an integer number (1037607885423).

Almost surely, 2^{4140003321341} is an apocalyptic number.

It is an amenable number.

4140003321341 is a deficient number, since it is larger than the sum of its proper divisors (10428220351).

4140003321341 is a wasteful number, since it uses less digits than its factorization.

4140003321341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10428220350.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 4140003321341 its reverse (1431233000414), we get a palindrome (5571236321755).

The spelling of 4140003321341 in words is "four trillion, one hundred forty billion, three million, three hundred twenty-one thousand, three hundred forty-one".