Base | Representation |
---|---|
bin | 111100001111101101001… |
… | …010000100000000111001 |
3 | 112122210010222020211110202 |
4 | 330033231022010000321 |
5 | 1020312241240002441 |
6 | 12445523221051545 |
7 | 605051601203132 |
oct | 74175512040071 |
9 | 15583128224422 |
10 | 4140032344121 |
11 | 1356861367393 |
12 | 56a448556bb5 |
13 | 2405322a365b |
14 | 104542d8ac89 |
15 | 72a5996a19b |
hex | 3c3ed284039 |
4140032344121 has 2 divisors, whose sum is σ = 4140032344122. Its totient is φ = 4140032344120.
The previous prime is 4140032344093. The next prime is 4140032344157. The reversal of 4140032344121 is 1214432300414.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2268638440000 + 1871393904121 = 1506200^2 + 1367989^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4140032344121 is a prime.
It is not a weakly prime, because it can be changed into another prime (4140032344181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2070016172060 + 2070016172061.
It is an arithmetic number, because the mean of its divisors is an integer number (2070016172061).
Almost surely, 24140032344121 is an apocalyptic number.
It is an amenable number.
4140032344121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4140032344121 is an equidigital number, since it uses as much as digits as its factorization.
4140032344121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 4140032344121 its reverse (1214432300414), we get a palindrome (5354464644535).
The spelling of 4140032344121 in words is "four trillion, one hundred forty billion, thirty-two million, three hundred forty-four thousand, one hundred twenty-one".
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