Base | Representation |
---|---|
bin | 10010110100111100001011… |
… | …00010010001011001011111 |
3 | 12102120221022211221102122220 |
4 | 21122132011202101121133 |
5 | 20411310112102320111 |
6 | 224015315431240423 |
7 | 11502104014364652 |
oct | 1132360542213137 |
9 | 172527284842586 |
10 | 41401430120031 |
11 | 1221227aa73743 |
12 | 4787a5b219113 |
13 | 1a141a45678b7 |
14 | a31ba89d7899 |
15 | 4bbe2d6c0e06 |
hex | 25a78589165f |
41401430120031 has 8 divisors (see below), whose sum is σ = 55490922046464. Its totient is φ = 27456445803480.
The previous prime is 41401430120027. The next prime is 41401430120047. The reversal of 41401430120031 is 13002103410414.
41401430120031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 41401430120031 - 22 = 41401430120027 is a prime.
It is a super-2 number, since 2×414014301200312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 41401430119983 and 41401430120010.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (41401430120021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36126901801 + ... + 36126902946.
It is an arithmetic number, because the mean of its divisors is an integer number (6936365255808).
Almost surely, 241401430120031 is an apocalyptic number.
41401430120031 is a deficient number, since it is larger than the sum of its proper divisors (14089491926433).
41401430120031 is a wasteful number, since it uses less digits than its factorization.
41401430120031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72253804941.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 41401430120031 its reverse (13002103410414), we get a palindrome (54403533530445).
The spelling of 41401430120031 in words is "forty-one trillion, four hundred one billion, four hundred thirty million, one hundred twenty thousand, thirty-one".
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