4140401300421 has 4 divisors (see below), whose sum is σ = 5520535067232. Its totient is φ = 2760267533612.

The previous prime is 4140401300419. The next prime is 4140401300437. The reversal of 4140401300421 is 1240031040414.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4140401300421 - 2¹ = 4140401300419 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4140401300391 and 4140401300400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4140401340421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 690066883401 + ... + 690066883406.

It is an arithmetic number, because the mean of its divisors is an integer number (1380133766808).

Almost surely, 2^{4140401300421} is an apocalyptic number.

It is an amenable number.

4140401300421 is a deficient number, since it is larger than the sum of its proper divisors (1380133766811).

4140401300421 is a wasteful number, since it uses less digits than its factorization.

4140401300421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1380133766810.

The product of its (nonzero) digits is 1536, while the sum is 24.

Adding to 4140401300421 its reverse (1240031040414), we get a palindrome (5380432340835).

The spelling of 4140401300421 in words is "four trillion, one hundred forty billion, four hundred one million, three hundred thousand, four hundred twenty-one".