414101100113 has 2 divisors, whose sum is σ = 414101100114. Its totient is φ = 414101100112.

The previous prime is 414101100089. The next prime is 414101100121. The reversal of 414101100113 is 311001101414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 251024046529 + 163077053584 = 501023^2 + 403828^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-414101100113 is a prime.

It is a super-2 number, since 2×414101100113² (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 414101100091 and 414101100100.

It is not a weakly prime, because it can be changed into another prime (414101120113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207050550056 + 207050550057.

It is an arithmetic number, because the mean of its divisors is an integer number (207050550057).

Almost surely, 2^414101100113 is an apocalyptic number.

It is an amenable number.

414101100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

414101100113 is an equidigital number, since it uses as much as digits as its factorization.

414101100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 414101100113 its reverse (311001101414), we get a palindrome (725102201527).

The spelling of 414101100113 in words is "four hundred fourteen billion, one hundred one million, one hundred thousand, one hundred thirteen".