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4141030121131 is a prime number
BaseRepresentation
bin111100010000101000101…
…000010001111010101011
3112122212201111202011012211
4330100220220101322223
51020321312202334011
612450210222545551
7605115405155041
oct74205050217253
915585644664184
104141030121131
111357223601a92
1256a6867382b7
13240660c12a57
141045d96ba391
1572ab735cb21
hex3c428a11eab

4141030121131 has 2 divisors, whose sum is σ = 4141030121132. Its totient is φ = 4141030121130.

The previous prime is 4141030121069. The next prime is 4141030121197. The reversal of 4141030121131 is 1311210301414.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4141030121131 is a prime.

It is a super-2 number, since 2×41410301211312 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4141030121731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2070515060565 + 2070515060566.

It is an arithmetic number, because the mean of its divisors is an integer number (2070515060566).

Almost surely, 24141030121131 is an apocalyptic number.

4141030121131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4141030121131 is an equidigital number, since it uses as much as digits as its factorization.

4141030121131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 4141030121131 its reverse (1311210301414), we get a palindrome (5452240422545).

The spelling of 4141030121131 in words is "four trillion, one hundred forty-one billion, thirty million, one hundred twenty-one thousand, one hundred thirty-one".