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414205055113 is a prime number
BaseRepresentation
bin1100000011100001000…
…10111001000010001001
31110121010122212221022011
412001300202321002021
523241242443230423
6514141055455521
741632246606603
oct6016042710211
91417118787264
10414205055113
1114a732a56573
12683385275a1
13300a05843b5
14160949b6173
15ab93a33b0d
hex60708b9089

414205055113 has 2 divisors, whose sum is σ = 414205055114. Its totient is φ = 414205055112.

The previous prime is 414205055101. The next prime is 414205055119. The reversal of 414205055113 is 311550502414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 402924066169 + 11280988944 = 634763^2 + 106212^2 .

It is a cyclic number.

It is not a de Polignac number, because 414205055113 - 213 = 414205046921 is a prime.

It is not a weakly prime, because it can be changed into another prime (414205055119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207102527556 + 207102527557.

It is an arithmetic number, because the mean of its divisors is an integer number (207102527557).

Almost surely, 2414205055113 is an apocalyptic number.

It is an amenable number.

414205055113 is a deficient number, since it is larger than the sum of its proper divisors (1).

414205055113 is an equidigital number, since it uses as much as digits as its factorization.

414205055113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 414205055113 its reverse (311550502414), we get a palindrome (725755557527).

The spelling of 414205055113 in words is "four hundred fourteen billion, two hundred five million, fifty-five thousand, one hundred thirteen".