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4142053625881 is a prime number
BaseRepresentation
bin111100010001100101101…
…000101001000000011001
3112122222100211122120210011
4330101211220221000121
51020330411212012011
612450455544121521
7605152643622643
oct74214550510031
915588324576704
104142053625881
1113576a931a286
1256a9114662a1
13240794c8c672
141046955c5893
1572b27133621
hex3c465a29019

4142053625881 has 2 divisors, whose sum is σ = 4142053625882. Its totient is φ = 4142053625880.

The previous prime is 4142053625789. The next prime is 4142053625893. The reversal of 4142053625881 is 1885263502414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4129901870656 + 12151755225 = 2032216^2 + 110235^2 .

It is a cyclic number.

It is not a de Polignac number, because 4142053625881 - 221 = 4142051528729 is a prime.

It is a super-2 number, since 2×41420536258812 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4142053626881) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2071026812940 + 2071026812941.

It is an arithmetic number, because the mean of its divisors is an integer number (2071026812941).

Almost surely, 24142053625881 is an apocalyptic number.

It is an amenable number.

4142053625881 is a deficient number, since it is larger than the sum of its proper divisors (1).

4142053625881 is an equidigital number, since it uses as much as digits as its factorization.

4142053625881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1843200, while the sum is 49.

The spelling of 4142053625881 in words is "four trillion, one hundred forty-two billion, fifty-three million, six hundred twenty-five thousand, eight hundred eighty-one".