Base | Representation |
---|---|
bin | 10010110101101010110011… |
… | …10000010101101011010011 |
3 | 12102200022221121021010111001 |
4 | 21122311121300111223103 |
5 | 20412212400121220333 |
6 | 224035015552402431 |
7 | 11503651301023516 |
oct | 1132653160255323 |
9 | 172608847233431 |
10 | 41426465413843 |
11 | 12221957816504 |
12 | 4790887546417 |
13 | 1a166641aa813 |
14 | a330a192ad7d |
15 | 4bc8e6515b7d |
hex | 25ad59c15ad3 |
41426465413843 has 2 divisors, whose sum is σ = 41426465413844. Its totient is φ = 41426465413842.
The previous prime is 41426465413831. The next prime is 41426465413889. The reversal of 41426465413843 is 34831456462414.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41426465413843 - 213 = 41426465405651 is a prime.
It is not a weakly prime, because it can be changed into another prime (41426465423843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20713232706921 + 20713232706922.
It is an arithmetic number, because the mean of its divisors is an integer number (20713232706922).
Almost surely, 241426465413843 is an apocalyptic number.
41426465413843 is a deficient number, since it is larger than the sum of its proper divisors (1).
41426465413843 is an equidigital number, since it uses as much as digits as its factorization.
41426465413843 is an evil number, because the sum of its binary digits is even.
The product of its digits is 26542080, while the sum is 55.
The spelling of 41426465413843 in words is "forty-one trillion, four hundred twenty-six billion, four hundred sixty-five million, four hundred thirteen thousand, eight hundred forty-three".
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