Base | Representation |
---|---|
bin | 10010110101110011100000… |
… | …11101011111001001101001 |
3 | 12102200210000110210112020221 |
4 | 21122321300131133021221 |
5 | 20412301434134041202 |
6 | 224041111545250041 |
7 | 11504205206362105 |
oct | 1132716035371151 |
9 | 172623013715227 |
10 | 41431141315177 |
11 | 1222393718a379 |
12 | 4791771493921 |
13 | 1a16c2ab51743 |
14 | a333c6944905 |
15 | 4bcabbc9d037 |
hex | 25ae7075f269 |
41431141315177 has 2 divisors, whose sum is σ = 41431141315178. Its totient is φ = 41431141315176.
The previous prime is 41431141315061. The next prime is 41431141315211. The reversal of 41431141315177 is 77151314113414.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 23294947802256 + 18136193512921 = 4826484^2 + 4258661^2 .
It is a cyclic number.
It is not a de Polignac number, because 41431141315177 - 231 = 41428993831529 is a prime.
It is not a weakly prime, because it can be changed into another prime (41431147315177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20715570657588 + 20715570657589.
It is an arithmetic number, because the mean of its divisors is an integer number (20715570657589).
Almost surely, 241431141315177 is an apocalyptic number.
It is an amenable number.
41431141315177 is a deficient number, since it is larger than the sum of its proper divisors (1).
41431141315177 is an equidigital number, since it uses as much as digits as its factorization.
41431141315177 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 141120, while the sum is 43.
The spelling of 41431141315177 in words is "forty-one trillion, four hundred thirty-one billion, one hundred forty-one million, three hundred fifteen thousand, one hundred seventy-seven".
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