Base | Representation |
---|---|
bin | 1100000011101101111… |
… | …11100110010000000011 |
3 | 1110121102012110111002001 |
4 | 12001312333212100003 |
5 | 23242003142244101 |
6 | 514155522404431 |
7 | 41635032315226 |
oct | 6016677462003 |
9 | 1417365414061 |
10 | 414313243651 |
11 | 14a78903018a |
12 | 68368800717 |
13 | 300b9b04098 |
14 | 160a50d95bd |
15 | ab9d2a4901 |
hex | 6076fe6403 |
414313243651 has 2 divisors, whose sum is σ = 414313243652. Its totient is φ = 414313243650.
The previous prime is 414313243613. The next prime is 414313243691. The reversal of 414313243651 is 156342313414.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-414313243651 is a prime.
It is a super-2 number, since 2×4143132436512 (a number of 24 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 414313243651.
It is not a weakly prime, because it can be changed into another prime (414313243691) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207156621825 + 207156621826.
It is an arithmetic number, because the mean of its divisors is an integer number (207156621826).
Almost surely, 2414313243651 is an apocalyptic number.
414313243651 is a deficient number, since it is larger than the sum of its proper divisors (1).
414313243651 is an equidigital number, since it uses as much as digits as its factorization.
414313243651 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 103680, while the sum is 37.
The spelling of 414313243651 in words is "four hundred fourteen billion, three hundred thirteen million, two hundred forty-three thousand, six hundred fifty-one".
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