Base | Representation |
---|---|
bin | 101111000111001010111111… |
… | …0101000100000010111100001 |
3 | 2000100021110002222002120211211 |
4 | 1132032111332220200113201 |
5 | 413304030341242231423 |
6 | 4025205400530310121 |
7 | 153200362652640334 |
oct | 13616257650402741 |
9 | 2010243088076754 |
10 | 414402044102113 |
11 | 11004aa13502871 |
12 | 3a589a86128341 |
13 | 14a2cc394590c2 |
14 | 744924753461b |
15 | 32d98350ea10d |
hex | 178e57ea205e1 |
414402044102113 has 2 divisors, whose sum is σ = 414402044102114. Its totient is φ = 414402044102112.
The previous prime is 414402044102021. The next prime is 414402044102201. The reversal of 414402044102113 is 311201440204414.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 272343464020224 + 142058580081889 = 16502832^2 + 11918833^2 .
It is a cyclic number.
It is not a de Polignac number, because 414402044102113 - 29 = 414402044101601 is a prime.
It is not a weakly prime, because it can be changed into another prime (414402048102113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 207201022051056 + 207201022051057.
It is an arithmetic number, because the mean of its divisors is an integer number (207201022051057).
Almost surely, 2414402044102113 is an apocalyptic number.
It is an amenable number.
414402044102113 is a deficient number, since it is larger than the sum of its proper divisors (1).
414402044102113 is an equidigital number, since it uses as much as digits as its factorization.
414402044102113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 414402044102113 its reverse (311201440204414), we get a palindrome (725603484306527).
The spelling of 414402044102113 in words is "four hundred fourteen trillion, four hundred two billion, forty-four million, one hundred two thousand, one hundred thirteen".
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