Base | Representation |
---|---|
bin | 101111000111001100011000… |
… | …0110110110111100000010111 |
3 | 2000100021201211100111212121102 |
4 | 1132032120300312313200113 |
5 | 413304103002224230401 |
6 | 4025211013342540315 |
7 | 153200530031310101 |
oct | 13616306066674027 |
9 | 2010251740455542 |
10 | 414405034211351 |
11 | 110051208328127 |
12 | 3a58a57b59769b |
13 | 14a302c4a89701 |
14 | 744944c6c4571 |
15 | 32d995c88856b |
hex | 178e630db7817 |
414405034211351 has 4 divisors (see below), whose sum is σ = 414405114142992. Its totient is φ = 414404954279712.
The previous prime is 414405034211341. The next prime is 414405034211381. The reversal of 414405034211351 is 153112430504414.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-414405034211351 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (414405034211341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31606226 + ... + 42752351.
It is an arithmetic number, because the mean of its divisors is an integer number (103601278535748).
Almost surely, 2414405034211351 is an apocalyptic number.
414405034211351 is a deficient number, since it is larger than the sum of its proper divisors (79931641).
414405034211351 is an equidigital number, since it uses as much as digits as its factorization.
414405034211351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 79931640.
The product of its (nonzero) digits is 115200, while the sum is 38.
Adding to 414405034211351 its reverse (153112430504414), we get a palindrome (567517464715765).
The spelling of 414405034211351 in words is "four hundred fourteen trillion, four hundred five billion, thirty-four million, two hundred eleven thousand, three hundred fifty-one".
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