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4144300633331 is a prime number
BaseRepresentation
bin111100010011101011100…
…100010010110011110011
3112200012011102210101112022
4330103223210102303303
51020400011430231311
612451510533222055
7605262430104035
oct74235344226363
915605142711468
104144300633331
111358651736231
1256b239a9192b
13240a6266c281
14104829bbbc55
1572c095385db
hex3c4eb912cf3

4144300633331 has 2 divisors, whose sum is σ = 4144300633332. Its totient is φ = 4144300633330.

The previous prime is 4144300633321. The next prime is 4144300633351. The reversal of 4144300633331 is 1333360034414.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 4144300633331 - 214 = 4144300616947 is a prime.

It is a super-2 number, since 2×41443006333312 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4144300633291 and 4144300633300.

It is not a weakly prime, because it can be changed into another prime (4144300633321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072150316665 + 2072150316666.

It is an arithmetic number, because the mean of its divisors is an integer number (2072150316666).

Almost surely, 24144300633331 is an apocalyptic number.

4144300633331 is a deficient number, since it is larger than the sum of its proper divisors (1).

4144300633331 is an equidigital number, since it uses as much as digits as its factorization.

4144300633331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 93312, while the sum is 35.

Adding to 4144300633331 its reverse (1333360034414), we get a palindrome (5477660667745).

The spelling of 4144300633331 in words is "four trillion, one hundred forty-four billion, three hundred million, six hundred thirty-three thousand, three hundred thirty-one".