4144300633341 has 12 divisors (see below), whose sum is σ = 6530413119360. Its totient is φ = 2511697353480.

The previous prime is 4144300633331. The next prime is 4144300633351. The reversal of 4144300633341 is 1433360034414.

4144300633341 is a `hidden beast` number, since 4 + 1 + 4 + 4 + 300 + 6 + 3 + 3 + 341 = 666.

It is an interprime number because it is at equal distance from previous prime (4144300633331) and next prime (4144300633351).

It is not a de Polignac number, because 4144300633341 - 2¹¹ = 4144300631293 is a prime.

It is a super-2 number, since 2×4144300633341² (a number of 26 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4144300633296 and 4144300633305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4144300633321) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 20930811181 + ... + 20930811378.

It is an arithmetic number, because the mean of its divisors is an integer number (544201093280).

Almost surely, 2^{4144300633341} is an apocalyptic number.

It is an amenable number.

4144300633341 is a deficient number, since it is larger than the sum of its proper divisors (2386112486019).

4144300633341 is a wasteful number, since it uses less digits than its factorization.

4144300633341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41861622576 (or 41861622573 counting only the distinct ones).

The product of its (nonzero) digits is 124416, while the sum is 36.

Adding to 4144300633341 its reverse (1433360034414), we get a palindrome (5577660667755).

The spelling of 4144300633341 in words is "four trillion, one hundred forty-four billion, three hundred million, six hundred thirty-three thousand, three hundred forty-one".