Base | Representation |
---|---|
bin | 111100010011110001100… |
… | …011100010111000001111 |
3 | 112200012102102211122022021 |
4 | 330103301203202320033 |
5 | 1020400213140202203 |
6 | 12451524522431011 |
7 | 605265060052462 |
oct | 74236143427017 |
9 | 15605372748267 |
10 | 4144401100303 |
11 | 13586a3416592 |
12 | 56b267662467 |
13 | 240a7a417499 |
14 | 1048392912d9 |
15 | 72c132815bd |
hex | 3c4f18e2e0f |
4144401100303 has 4 divisors (see below), whose sum is σ = 4147301312440. Its totient is φ = 4141500888168.
The previous prime is 4144401100267. The next prime is 4144401100309. The reversal of 4144401100303 is 3030011044414.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4144401100303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4144401100309) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1450103925 + ... + 1450106782.
It is an arithmetic number, because the mean of its divisors is an integer number (1036825328110).
Almost surely, 24144401100303 is an apocalyptic number.
4144401100303 is a deficient number, since it is larger than the sum of its proper divisors (2900212137).
4144401100303 is a wasteful number, since it uses less digits than its factorization.
4144401100303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2900212136.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 4144401100303 its reverse (3030011044414), we get a palindrome (7174412144717).
The spelling of 4144401100303 in words is "four trillion, one hundred forty-four billion, four hundred one million, one hundred thousand, three hundred three".
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