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4145054131 is a prime number
BaseRepresentation
bin1111011100010000…
…1000000110110011
3101200212122120022101
43313010020012303
531442113213011
61523150521231
7204501243631
oct36704100663
911625576271
104145054131
111837858579
12978206217
135109ab36a
142b4712351
15193d792c1
hexf71081b3

4145054131 has 2 divisors, whose sum is σ = 4145054132. Its totient is φ = 4145054130.

The previous prime is 4145054107. The next prime is 4145054141. The reversal of 4145054131 is 1314505414.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4145054131 is a prime.

It is a super-2 number, since 2×41450541312 = 34362947497840330322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4145054131.

It is not a weakly prime, because it can be changed into another prime (4145054141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072527065 + 2072527066.

It is an arithmetic number, because the mean of its divisors is an integer number (2072527066).

Almost surely, 24145054131 is an apocalyptic number.

4145054131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4145054131 is an equidigital number, since it uses as much as digits as its factorization.

4145054131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4800, while the sum is 28.

The square root of 4145054131 is about 64382.0948012722. The cubic root of 4145054131 is about 1606.3619267925.

Adding to 4145054131 its reverse (1314505414), we get a palindrome (5459559545).

It can be divided in two parts, 414505413 and 1, that added together give a palindrome (414505414).

The spelling of 4145054131 in words is "four billion, one hundred forty-five million, fifty-four thousand, one hundred thirty-one".