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4145500424353 is a prime number
BaseRepresentation
bin111100010100110011000…
…101001000100010100001
3112200022021001102002101211
4330110303011020202201
51020404441102034403
612452225553030121
7605334236132041
oct74246305104241
915608231362354
104145500424353
111359107a09a62
1256b513855341
13240bc40bc5a2
14104901295721
1572c79a3206d
hex3c5331488a1

4145500424353 has 2 divisors, whose sum is σ = 4145500424354. Its totient is φ = 4145500424352.

The previous prime is 4145500424243. The next prime is 4145500424423. The reversal of 4145500424353 is 3534240055414.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3945057971089 + 200442453264 = 1986217^2 + 447708^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4145500424353 is a prime.

It is not a weakly prime, because it can be changed into another prime (4145500424453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2072750212176 + 2072750212177.

It is an arithmetic number, because the mean of its divisors is an integer number (2072750212177).

Almost surely, 24145500424353 is an apocalyptic number.

It is an amenable number.

4145500424353 is a deficient number, since it is larger than the sum of its proper divisors (1).

4145500424353 is an equidigital number, since it uses as much as digits as its factorization.

4145500424353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576000, while the sum is 40.

Adding to 4145500424353 its reverse (3534240055414), we get a palindrome (7679740479767).

The spelling of 4145500424353 in words is "four trillion, one hundred forty-five billion, five hundred million, four hundred twenty-four thousand, three hundred fifty-three".