41491433 has 2 divisors, whose sum is σ = 41491434. Its totient is φ = 41491432.

The previous prime is 41491403. The next prime is 41491469. The reversal of 41491433 is 33419414.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 38775529 + 2715904 = 6227^2 + 1648^2 .

It is a cyclic number.

It is not a de Polignac number, because 41491433 - 2¹⁰ = 41490409 is a prime.

It is a Chen prime.

It is equal to p_2518760 and since 41491433 and 2518760 have the same sum of digits, it is a Honaker prime.

It is a junction number, because it is equal to n+sod(n) for n = 41491396 and 41491405.

It is not a weakly prime, because it can be changed into another prime (41491403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20745716 + 20745717.

It is an arithmetic number, because the mean of its divisors is an integer number (20745717).

Almost surely, 2^41491433 is an apocalyptic number.

It is an amenable number.

41491433 is a deficient number, since it is larger than the sum of its proper divisors (1).

41491433 is an equidigital number, since it uses as much as digits as its factorization.

41491433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 29.

The square root of 41491433 is about 6441.3844008877. The cubic root of 41491433 is about 346.1939533154.

The spelling of 41491433 in words is "forty-one million, four hundred ninety-one thousand, four hundred thirty-three".