Base | Representation |
---|---|
bin | 100110101001110011… |
… | …011100001101010011 |
3 | 10222010110020021201001 |
4 | 212221303130031103 |
5 | 1134444401240201 |
6 | 31022204522431 |
7 | 2666332161331 |
oct | 465163341523 |
9 | 128113207631 |
10 | 41503540051 |
11 | 16668736a26 |
12 | 8063550417 |
13 | 3bb5713c2c |
14 | 201a152b51 |
15 | 112d9d0301 |
hex | 9a9cdc353 |
41503540051 has 2 divisors, whose sum is σ = 41503540052. Its totient is φ = 41503540050.
The previous prime is 41503540027. The next prime is 41503540061. The reversal of 41503540051 is 15004530514.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41503540051 is a prime.
It is a super-3 number, since 3×415035400513 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (41503540061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20751770025 + 20751770026.
It is an arithmetic number, because the mean of its divisors is an integer number (20751770026).
Almost surely, 241503540051 is an apocalyptic number.
41503540051 is a deficient number, since it is larger than the sum of its proper divisors (1).
41503540051 is an equidigital number, since it uses as much as digits as its factorization.
41503540051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6000, while the sum is 28.
The spelling of 41503540051 in words is "forty-one billion, five hundred three million, five hundred forty thousand, fifty-one".
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