Base | Representation |
---|---|
bin | 10010111000101110011110… |
… | …01101010101110110110011 |
3 | 12110001101002200220110121021 |
4 | 21130113033031111312303 |
5 | 20420423020340304011 |
6 | 224155151545240311 |
7 | 11514360443133064 |
oct | 1134271715256663 |
9 | 173041080813537 |
10 | 41531515166131 |
11 | 12262464650201 |
12 | 47a9104493097 |
13 | 1a23535c48563 |
14 | a381c94c056b |
15 | 4c04e3c33471 |
hex | 25c5cf355db3 |
41531515166131 has 2 divisors, whose sum is σ = 41531515166132. Its totient is φ = 41531515166130.
The previous prime is 41531515166083. The next prime is 41531515166137. The reversal of 41531515166131 is 13166151513514.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41531515166131 - 27 = 41531515166003 is a prime.
It is a super-2 number, since 2×415315151661312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41531515166137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20765757583065 + 20765757583066.
It is an arithmetic number, because the mean of its divisors is an integer number (20765757583066).
Almost surely, 241531515166131 is an apocalyptic number.
41531515166131 is a deficient number, since it is larger than the sum of its proper divisors (1).
41531515166131 is an equidigital number, since it uses as much as digits as its factorization.
41531515166131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 162000, while the sum is 43.
Adding to 41531515166131 its reverse (13166151513514), we get a palindrome (54697666679645).
The spelling of 41531515166131 in words is "forty-one trillion, five hundred thirty-one billion, five hundred fifteen million, one hundred sixty-six thousand, one hundred thirty-one".
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