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415345212111 = 3138448404037
BaseRepresentation
bin1100000101101001000…
…00001111101011001111
31110201002010021220200010
412002310200033223033
523301111333241421
6514450145204303
742002433023514
oct6026440175317
91421063256603
10415345212111
111501685a9385
12685b6330693
13302228551cb
14161621a930b
15ac0db9d076
hex60b480facf

415345212111 has 4 divisors (see below), whose sum is σ = 553793616152. Its totient is φ = 276896808072.

The previous prime is 415345212077. The next prime is 415345212127. The reversal of 415345212111 is 111212543514.

It is a semiprime because it is the product of two primes.

It is a de Polignac number, because none of the positive numbers 2k-415345212111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (415345212311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69224202016 + ... + 69224202021.

It is an arithmetic number, because the mean of its divisors is an integer number (138448404038).

Almost surely, 2415345212111 is an apocalyptic number.

415345212111 is a deficient number, since it is larger than the sum of its proper divisors (138448404041).

415345212111 is a wasteful number, since it uses less digits than its factorization.

415345212111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 138448404040.

The product of its digits is 4800, while the sum is 30.

Adding to 415345212111 its reverse (111212543514), we get a palindrome (526557755625).

The spelling of 415345212111 in words is "four hundred fifteen billion, three hundred forty-five million, two hundred twelve thousand, one hundred eleven".

Divisors: 1 3 138448404037 415345212111