Base | Representation |
---|---|
bin | 10010111000111000111000… |
… | …00110111000100011000011 |
3 | 12110001220111221021221221011 |
4 | 21130130130012320203003 |
5 | 20421020440133124042 |
6 | 224201514101541351 |
7 | 11514646031643604 |
oct | 1134343406704303 |
9 | 173056457257834 |
10 | 41537100286147 |
11 | 12264870272574 |
12 | 47aa202a14857 |
13 | 1a23c16092bbb |
14 | a38599173dab |
15 | 4c071e218a17 |
hex | 25c71c1b88c3 |
41537100286147 has 2 divisors, whose sum is σ = 41537100286148. Its totient is φ = 41537100286146.
The previous prime is 41537100286127. The next prime is 41537100286153. The reversal of 41537100286147 is 74168200173514.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-41537100286147 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 41537100286147.
It is not a weakly prime, because it can be changed into another prime (41537100286127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20768550143073 + 20768550143074.
It is an arithmetic number, because the mean of its divisors is an integer number (20768550143074).
Almost surely, 241537100286147 is an apocalyptic number.
41537100286147 is a deficient number, since it is larger than the sum of its proper divisors (1).
41537100286147 is an equidigital number, since it uses as much as digits as its factorization.
41537100286147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1128960, while the sum is 49.
The spelling of 41537100286147 in words is "forty-one trillion, five hundred thirty-seven billion, one hundred million, two hundred eighty-six thousand, one hundred forty-seven".
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