Base | Representation |
---|---|
bin | 1111011110101110… |
… | …0111001100111001 |
3 | 101201121010110012002 |
4 | 3313223213030321 |
5 | 32002240430423 |
6 | 1524200430345 |
7 | 204655234466 |
oct | 36753471471 |
9 | 11647113162 |
10 | 4155405113 |
11 | 1842688402 |
12 | 97b7783b5 |
13 | 512b938c2 |
14 | 2b5c4866d |
15 | 194c21228 |
hex | f7ae7339 |
4155405113 has 2 divisors, whose sum is σ = 4155405114. Its totient is φ = 4155405112.
The previous prime is 4155405103. The next prime is 4155405131. The reversal of 4155405113 is 3115045514.
Together with next prime (4155405131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2471780089 + 1683625024 = 49717^2 + 41032^2 .
It is a cyclic number.
It is not a de Polignac number, because 4155405113 - 26 = 4155405049 is a prime.
It is a super-3 number, since 3×41554051133 (a number of 30 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (4155405103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2077702556 + 2077702557.
It is an arithmetic number, because the mean of its divisors is an integer number (2077702557).
Almost surely, 24155405113 is an apocalyptic number.
It is an amenable number.
4155405113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4155405113 is an equidigital number, since it uses as much as digits as its factorization.
4155405113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6000, while the sum is 29.
The square root of 4155405113 is about 64462.4317955815. The cubic root of 4155405113 is about 1607.6979448862.
The spelling of 4155405113 in words is "four billion, one hundred fifty-five million, four hundred five thousand, one hundred thirteen".
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