Base | Representation |
---|---|
bin | 10010111001101111101101… |
… | …11011110000110101101011 |
3 | 12110011201111201220202011021 |
4 | 21130313312323300311223 |
5 | 20422011234043310232 |
6 | 224223223330513311 |
7 | 11520040434106336 |
oct | 1134676673606553 |
9 | 173151451822137 |
10 | 41566541385067 |
11 | 122762a8a79986 |
12 | 47b3a5a735837 |
13 | 1a2692871c1aa |
14 | a39b8d29361d |
15 | 4c1393c42397 |
hex | 25cdf6ef0d6b |
41566541385067 has 2 divisors, whose sum is σ = 41566541385068. Its totient is φ = 41566541385066.
The previous prime is 41566541385049. The next prime is 41566541385107. The reversal of 41566541385067 is 76058314566514.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 41566541385067 - 223 = 41566532996459 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41566541384996 and 41566541385014.
It is not a weakly prime, because it can be changed into another prime (41566541385167) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20783270692533 + 20783270692534.
It is an arithmetic number, because the mean of its divisors is an integer number (20783270692534).
Almost surely, 241566541385067 is an apocalyptic number.
41566541385067 is a deficient number, since it is larger than the sum of its proper divisors (1).
41566541385067 is an equidigital number, since it uses as much as digits as its factorization.
41566541385067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72576000, while the sum is 61.
The spelling of 41566541385067 in words is "forty-one trillion, five hundred sixty-six billion, five hundred forty-one million, three hundred eighty-five thousand, sixty-seven".
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