Base | Representation |
---|---|
bin | 10010111010101111010001… |
… | …01101001010000001011011 |
3 | 12110021222120200122120122111 |
4 | 21131113220231022001123 |
5 | 20423041124034212103 |
6 | 224251025214533151 |
7 | 11522356124055142 |
oct | 1135275055120133 |
9 | 173258520576574 |
10 | 41600662413403 |
11 | 12289818450555 |
12 | 47ba5a18071b7 |
13 | 1a29c057cc9a2 |
14 | a3b6a8b58759 |
15 | 4c21de54b86d |
hex | 25d5e8b4a05b |
41600662413403 has 2 divisors, whose sum is σ = 41600662413404. Its totient is φ = 41600662413402.
The previous prime is 41600662413281. The next prime is 41600662413421. The reversal of 41600662413403 is 30431426600614.
41600662413403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41600662413403 - 217 = 41600662282331 is a prime.
It is a super-2 number, since 2×416006624134032 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (41600662413473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20800331206701 + 20800331206702.
It is an arithmetic number, because the mean of its divisors is an integer number (20800331206702).
Almost surely, 241600662413403 is an apocalyptic number.
41600662413403 is a deficient number, since it is larger than the sum of its proper divisors (1).
41600662413403 is an equidigital number, since it uses as much as digits as its factorization.
41600662413403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 248832, while the sum is 40.
The spelling of 41600662413403 in words is "forty-one trillion, six hundred billion, six hundred sixty-two million, four hundred thirteen thousand, four hundred three".
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