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41605262333113 is a prime number
BaseRepresentation
bin10010111010110111110101…
…11000011101010010111001
312110022102110021012201020011
421131123322320131102321
520423130034124124423
6224253105455101521
711522611120534603
oct1135337270352271
9173272407181204
1041605262333113
1112290768a38296
1247bb4662118a1
131a2a4897bc57b
14a3b9c3a34173
154c23ad2c5b0d
hex25d6fae1d4b9

41605262333113 has 2 divisors, whose sum is σ = 41605262333114. Its totient is φ = 41605262333112.

The previous prime is 41605262333101. The next prime is 41605262333137. The reversal of 41605262333113 is 31133326250614.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37327798683904 + 4277463649209 = 6109648^2 + 2068203^2 .

It is a cyclic number.

It is not a de Polignac number, because 41605262333113 - 213 = 41605262324921 is a prime.

It is not a weakly prime, because it can be changed into another prime (41605262333153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20802631166556 + 20802631166557.

It is an arithmetic number, because the mean of its divisors is an integer number (20802631166557).

Almost surely, 241605262333113 is an apocalyptic number.

It is an amenable number.

41605262333113 is a deficient number, since it is larger than the sum of its proper divisors (1).

41605262333113 is an equidigital number, since it uses as much as digits as its factorization.

41605262333113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 233280, while the sum is 40.

Adding to 41605262333113 its reverse (31133326250614), we get a palindrome (72738588583727).

The spelling of 41605262333113 in words is "forty-one trillion, six hundred five billion, two hundred sixty-two million, three hundred thirty-three thousand, one hundred thirteen".