Base | Representation |
---|---|
bin | 111100101000100110011… |
… | …111111001111011101001 |
3 | 112202100010221220112202002 |
4 | 330220212133321323221 |
5 | 1021232013112100311 |
6 | 12510103545020345 |
7 | 610016205052304 |
oct | 74504637717351 |
9 | 15670127815662 |
10 | 4166764175081 |
11 | 1367129827672 |
12 | 573668a846b5 |
13 | 242c0254c901 |
14 | 10595b343b3b |
15 | 735c16cc93b |
hex | 3ca267f9ee9 |
4166764175081 has 2 divisors, whose sum is σ = 4166764175082. Its totient is φ = 4166764175080.
The previous prime is 4166764175069. The next prime is 4166764175129. The reversal of 4166764175081 is 1805714676614.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3712095822400 + 454668352681 = 1926680^2 + 674291^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4166764175081 is a prime.
It is a super-2 number, since 2×41667641750812 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4166764175881) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2083382087540 + 2083382087541.
It is an arithmetic number, because the mean of its divisors is an integer number (2083382087541).
Almost surely, 24166764175081 is an apocalyptic number.
It is an amenable number.
4166764175081 is a deficient number, since it is larger than the sum of its proper divisors (1).
4166764175081 is an equidigital number, since it uses as much as digits as its factorization.
4166764175081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6773760, while the sum is 56.
The spelling of 4166764175081 in words is "four trillion, one hundred sixty-six billion, seven hundred sixty-four million, one hundred seventy-five thousand, eighty-one".
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