4170742840753 has 2 divisors, whose sum is σ = 4170742840754. Its totient is φ = 4170742840752.

The previous prime is 4170742840741. The next prime is 4170742840769. The reversal of 4170742840753 is 3570482470714.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3838590029824 + 332152810929 = 1959232^2 + 576327^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4170742840753 is a prime.

It is a super-3 number, since 3×4170742840753³ (a number of 39 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4170742840753.

It is not a weakly prime, because it can be changed into another prime (4170742840153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2085371420376 + 2085371420377.

It is an arithmetic number, because the mean of its divisors is an integer number (2085371420377).

Almost surely, 2^{4170742840753} is an apocalyptic number.

It is an amenable number.

4170742840753 is a deficient number, since it is larger than the sum of its proper divisors (1).

4170742840753 is an equidigital number, since it uses as much as digits as its factorization.

4170742840753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5268480, while the sum is 52.

The spelling of 4170742840753 in words is "four trillion, one hundred seventy billion, seven hundred forty-two million, eight hundred forty thousand, seven hundred fifty-three".