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41968292072713 is a prime number
BaseRepresentation
bin10011000101011100000010…
…01001000000110100001001
312111121010111102201021010021
421202232001021000310021
521000102030232311323
6225131544530220441
711561052254443066
oct1142560111006411
9174533442637107
1041968292072713
111241071a844876
1248598a0124721
131a55792973186
14a513c1b73c6d
154cba591a305d
hex262b81240d09

41968292072713 has 2 divisors, whose sum is σ = 41968292072714. Its totient is φ = 41968292072712.

The previous prime is 41968292072687. The next prime is 41968292072731. The reversal of 41968292072713 is 31727029286914.

Together with next prime (41968292072731) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 40355361592569 + 1612930480144 = 6352587^2 + 1270012^2 .

It is a cyclic number.

It is not a de Polignac number, because 41968292072713 - 225 = 41968258518281 is a prime.

It is a super-2 number, since 2×419682920727132 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (41968292076713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20984146036356 + 20984146036357.

It is an arithmetic number, because the mean of its divisors is an integer number (20984146036357).

Almost surely, 241968292072713 is an apocalyptic number.

It is an amenable number.

41968292072713 is a deficient number, since it is larger than the sum of its proper divisors (1).

41968292072713 is an equidigital number, since it uses as much as digits as its factorization.

41968292072713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18289152, while the sum is 61.

The spelling of 41968292072713 in words is "forty-one trillion, nine hundred sixty-eight billion, two hundred ninety-two million, seventy-two thousand, seven hundred thirteen".