Base | Representation |
---|---|
bin | 10011000110010001010010… |
… | …01000010000010011010011 |
3 | 12111200212021210102010220202 |
4 | 21203020221020100103103 |
5 | 21001034102321000232 |
6 | 225153033410125415 |
7 | 11563113562105661 |
oct | 1143105110202323 |
9 | 174625253363822 |
10 | 41996880250067 |
11 | 12421860054626 |
12 | 486333a28086b |
13 | 1a5839a6aa452 |
14 | a529348adc31 |
15 | 4cc67dd9e162 |
hex | 2632292104d3 |
41996880250067 has 2 divisors, whose sum is σ = 41996880250068. Its totient is φ = 41996880250066.
The previous prime is 41996880249997. The next prime is 41996880250121. The reversal of 41996880250067 is 76005208869914.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 41996880250067 - 222 = 41996876055763 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 41996880249985 and 41996880250012.
It is not a weakly prime, because it can be changed into another prime (41996880250667) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20998440125033 + 20998440125034.
It is an arithmetic number, because the mean of its divisors is an integer number (20998440125034).
Almost surely, 241996880250067 is an apocalyptic number.
41996880250067 is a deficient number, since it is larger than the sum of its proper divisors (1).
41996880250067 is an equidigital number, since it uses as much as digits as its factorization.
41996880250067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 52254720, while the sum is 65.
The spelling of 41996880250067 in words is "forty-one trillion, nine hundred ninety-six billion, eight hundred eighty million, two hundred fifty thousand, sixty-seven".
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