Base | Representation |
---|---|
bin | 1100001110010111110… |
… | …11001010110000110111 |
3 | 1111011011211101221221021 |
4 | 12013023323022300313 |
5 | 23340211434110033 |
6 | 520543251202011 |
7 | 42226545360460 |
oct | 6071373126067 |
9 | 1434154357837 |
10 | 420033113143 |
11 | 152153818856 |
12 | 694a42a6307 |
13 | 307bbb3ac47 |
14 | 16488a27d67 |
15 | add5505b2d |
hex | 61cbecac37 |
420033113143 has 4 divisors (see below), whose sum is σ = 480037843600. Its totient is φ = 360028382688.
The previous prime is 420033113117. The next prime is 420033113189. The reversal of 420033113143 is 341311330024.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 420033113143 - 217 = 420032982071 is a prime.
It is a super-2 number, since 2×4200331131432 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (420033113743) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30002365218 + ... + 30002365231.
It is an arithmetic number, because the mean of its divisors is an integer number (120009460900).
Almost surely, 2420033113143 is an apocalyptic number.
420033113143 is a deficient number, since it is larger than the sum of its proper divisors (60004730457).
420033113143 is an equidigital number, since it uses as much as digits as its factorization.
420033113143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60004730456.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 420033113143 its reverse (341311330024), we get a palindrome (761344443167).
The spelling of 420033113143 in words is "four hundred twenty billion, thirty-three million, one hundred thirteen thousand, one hundred forty-three".
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