Base | Representation |
---|---|
bin | 111101000111111100000… |
… | …001100101011100101001 |
3 | 112212112222212221201100101 |
4 | 331013330001211130221 |
5 | 1022304420244302103 |
6 | 12533350424105401 |
7 | 612320052066064 |
oct | 75077401453451 |
9 | 15775885851311 |
10 | 4200411322153 |
11 | 137a425761232 |
12 | 57a099305261 |
13 | 2461353c17a7 |
14 | 10742dcd18db |
15 | 743e05cca1d |
hex | 3d1fc065729 |
4200411322153 has 2 divisors, whose sum is σ = 4200411322154. Its totient is φ = 4200411322152.
The previous prime is 4200411322139. The next prime is 4200411322169. The reversal of 4200411322153 is 3512231140024.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3774926468889 + 425484853264 = 1942917^2 + 652292^2 .
It is a cyclic number.
It is not a de Polignac number, because 4200411322153 - 29 = 4200411321641 is a prime.
It is a super-2 number, since 2×42004113221532 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4200411322253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2100205661076 + 2100205661077.
It is an arithmetic number, because the mean of its divisors is an integer number (2100205661077).
Almost surely, 24200411322153 is an apocalyptic number.
It is an amenable number.
4200411322153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4200411322153 is an equidigital number, since it uses as much as digits as its factorization.
4200411322153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 4200411322153 its reverse (3512231140024), we get a palindrome (7712642462177).
The spelling of 4200411322153 in words is "four trillion, two hundred billion, four hundred eleven million, three hundred twenty-two thousand, one hundred fifty-three".
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