Base | Representation |
---|---|
bin | 1100001110011000111… |
… | …10101010111110100011 |
3 | 1111011012110220210201112 |
4 | 12013030132222332203 |
5 | 23340221324421011 |
6 | 520544222453535 |
7 | 42230020442525 |
oct | 6071436527643 |
9 | 1434173823645 |
10 | 420042420131 |
11 | 152158aa5284 |
12 | 694a74342ab |
13 | 307c0a49239 |
14 | 16489d6ba15 |
15 | add624358b |
hex | 61cc7aafa3 |
420042420131 has 2 divisors, whose sum is σ = 420042420132. Its totient is φ = 420042420130.
The previous prime is 420042420073. The next prime is 420042420209. The reversal of 420042420131 is 131024240024.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 420042420131 - 226 = 419975311267 is a prime.
It is a super-3 number, since 3×4200424201313 (a number of 36 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 420042420097 and 420042420106.
It is not a weakly prime, because it can be changed into another prime (420042420431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 210021210065 + 210021210066.
It is an arithmetic number, because the mean of its divisors is an integer number (210021210066).
Almost surely, 2420042420131 is an apocalyptic number.
420042420131 is a deficient number, since it is larger than the sum of its proper divisors (1).
420042420131 is an equidigital number, since it uses as much as digits as its factorization.
420042420131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1536, while the sum is 23.
Adding to 420042420131 its reverse (131024240024), we get a palindrome (551066660155).
The spelling of 420042420131 in words is "four hundred twenty billion, forty-two million, four hundred twenty thousand, one hundred thirty-one".
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