Base | Representation |
---|---|
bin | 111101001000110111101… |
… | …011010101100101111011 |
3 | 112212122120122010200000112 |
4 | 331020313223111211323 |
5 | 1022313443000414003 |
6 | 12534034014454535 |
7 | 612353623543604 |
oct | 75106753254573 |
9 | 15778518120015 |
10 | 4201412123003 |
11 | 137a899681777 |
12 | 57a31850444b |
13 | 24626484c344 |
14 | 1074c6baadab |
15 | 7444d3bb3d8 |
hex | 3d237ad597b |
4201412123003 has 2 divisors, whose sum is σ = 4201412123004. Its totient is φ = 4201412123002.
The previous prime is 4201412122993. The next prime is 4201412123087. The reversal of 4201412123003 is 3003212141024.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4201412123003 - 222 = 4201407928699 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 4201412123003.
It is not a weakly prime, because it can be changed into another prime (4201412123603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2100706061501 + 2100706061502.
It is an arithmetic number, because the mean of its divisors is an integer number (2100706061502).
Almost surely, 24201412123003 is an apocalyptic number.
4201412123003 is a deficient number, since it is larger than the sum of its proper divisors (1).
4201412123003 is an equidigital number, since it uses as much as digits as its factorization.
4201412123003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4201412123003 its reverse (3003212141024), we get a palindrome (7204624264027).
The spelling of 4201412123003 in words is "four trillion, two hundred one billion, four hundred twelve million, one hundred twenty-three thousand, three".
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