Base | Representation |
---|---|
bin | 111101010010000110111… |
… | …100111011011001010011 |
3 | 112220121011222021010121212 |
4 | 331102012330323121103 |
5 | 1022444302002201242 |
6 | 12542354221410335 |
7 | 613154506646033 |
oct | 75220674733123 |
9 | 15817158233555 |
10 | 4211332068947 |
11 | 138401a188a03 |
12 | 5802267099ab |
13 | 247185a8a943 |
14 | 107b884518c3 |
15 | 7482e214782 |
hex | 3d486f3b653 |
4211332068947 has 2 divisors, whose sum is σ = 4211332068948. Its totient is φ = 4211332068946.
The previous prime is 4211332068893. The next prime is 4211332068961. The reversal of 4211332068947 is 7498602331124.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4211332068947 - 210 = 4211332067923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4211332068895 and 4211332068904.
It is not a weakly prime, because it can be changed into another prime (4211332068847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2105666034473 + 2105666034474.
It is an arithmetic number, because the mean of its divisors is an integer number (2105666034474).
Almost surely, 24211332068947 is an apocalyptic number.
4211332068947 is a deficient number, since it is larger than the sum of its proper divisors (1).
4211332068947 is an equidigital number, since it uses as much as digits as its factorization.
4211332068947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1741824, while the sum is 50.
The spelling of 4211332068947 in words is "four trillion, two hundred eleven billion, three hundred thirty-two million, sixty-eight thousand, nine hundred forty-seven".
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