Base | Representation |
---|---|
bin | 111101010011001111110… |
… | …110101000011010111011 |
3 | 112220201100012201100110011 |
4 | 331103033312220122323 |
5 | 1023004303104431011 |
6 | 12543115432402351 |
7 | 613230021006001 |
oct | 75231766503273 |
9 | 15821305640404 |
10 | 4212555155131 |
11 | 1384597622734 |
12 | 5805082463b7 |
13 | 24731c2a618b |
14 | 107c62a70a71 |
15 | 748a17b0621 |
hex | 3d4cfda86bb |
4212555155131 has 2 divisors, whose sum is σ = 4212555155132. Its totient is φ = 4212555155130.
The previous prime is 4212555155099. The next prime is 4212555155189. The reversal of 4212555155131 is 1315515552124.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4212555155131 - 25 = 4212555155099 is a prime.
It is a super-2 number, since 2×42125551551312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4212555155531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2106277577565 + 2106277577566.
It is an arithmetic number, because the mean of its divisors is an integer number (2106277577566).
Almost surely, 24212555155131 is an apocalyptic number.
4212555155131 is a deficient number, since it is larger than the sum of its proper divisors (1).
4212555155131 is an equidigital number, since it uses as much as digits as its factorization.
4212555155131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 150000, while the sum is 40.
The spelling of 4212555155131 in words is "four trillion, two hundred twelve billion, five hundred fifty-five million, one hundred fifty-five thousand, one hundred thirty-one".
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