Base | Representation |
---|---|
bin | 10011001010001010000010… |
… | …11001001110111000010011 |
3 | 12112011122000012100110012211 |
4 | 21211011001121032320103 |
5 | 21010231110410340201 |
6 | 225334241501332551 |
7 | 11605552235460235 |
oct | 1145050131167023 |
9 | 175148005313184 |
10 | 42130431340051 |
11 | 1247346317616a |
12 | 48851b0267157 |
13 | 1a67b62198b52 |
14 | a591a3836255 |
15 | 4d0d98862651 |
hex | 26514164ee13 |
42130431340051 has 2 divisors, whose sum is σ = 42130431340052. Its totient is φ = 42130431340050.
The previous prime is 42130431340009. The next prime is 42130431340133. The reversal of 42130431340051 is 15004313403124.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 42130431340051 - 221 = 42130429242899 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 42130431339995 and 42130431340022.
It is not a weakly prime, because it can be changed into another prime (42130431340951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21065215670025 + 21065215670026.
It is an arithmetic number, because the mean of its divisors is an integer number (21065215670026).
Almost surely, 242130431340051 is an apocalyptic number.
42130431340051 is a deficient number, since it is larger than the sum of its proper divisors (1).
42130431340051 is an equidigital number, since it uses as much as digits as its factorization.
42130431340051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 42130431340051 its reverse (15004313403124), we get a palindrome (57134744743175).
The spelling of 42130431340051 in words is "forty-two trillion, one hundred thirty billion, four hundred thirty-one million, three hundred forty thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 5.076 sec. • engine limits •