Base | Representation |
---|---|
bin | 111101010011110111000… |
… | …101000001111100011001 |
3 | 112220210001002000120201001 |
4 | 331103313011001330121 |
5 | 1023012130042203423 |
6 | 12543305021425001 |
7 | 613252231441012 |
oct | 75236705017431 |
9 | 15823032016631 |
10 | 4213213241113 |
11 | 13848a5044448 |
12 | 58067070b161 |
13 | 2473c572b776 |
14 | 107cc6218009 |
15 | 748de453cad |
hex | 3d4f7141f19 |
4213213241113 has 2 divisors, whose sum is σ = 4213213241114. Its totient is φ = 4213213241112.
The previous prime is 4213213241093. The next prime is 4213213241123. The reversal of 4213213241113 is 3111423123124.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3291129337609 + 922083903504 = 1814147^2 + 960252^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4213213241113 is a prime.
It is not a weakly prime, because it can be changed into another prime (4213213241123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2106606620556 + 2106606620557.
It is an arithmetic number, because the mean of its divisors is an integer number (2106606620557).
Almost surely, 24213213241113 is an apocalyptic number.
It is an amenable number.
4213213241113 is a deficient number, since it is larger than the sum of its proper divisors (1).
4213213241113 is an equidigital number, since it uses as much as digits as its factorization.
4213213241113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3456, while the sum is 28.
Adding to 4213213241113 its reverse (3111423123124), we get a palindrome (7324636364237).
The spelling of 4213213241113 in words is "four trillion, two hundred thirteen billion, two hundred thirteen million, two hundred forty-one thousand, one hundred thirteen".
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