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42203413303 = 93414518083
BaseRepresentation
bin100111010011100001…
…001111101100110111
311000221020011112022121
4213103201033230313
51142413033211203
631215445340411
73022561044202
oct472341175467
9130836145277
1042203413303
11169977aa077
128219a07707
133c9770a70c
142085096939
15117017a0bd
hex9d384fb37

42203413303 has 4 divisors (see below), whose sum is σ = 42207940728. Its totient is φ = 42198885880.

The previous prime is 42203413279. The next prime is 42203413313. The reversal of 42203413303 is 30331430224.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 42203413303 - 25 = 42203413271 is a prime.

It is a super-4 number, since 4×422034133034 (a number of 44 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (42203413313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2249701 + ... + 2268382.

It is an arithmetic number, because the mean of its divisors is an integer number (10551985182).

Almost surely, 242203413303 is an apocalyptic number.

42203413303 is a deficient number, since it is larger than the sum of its proper divisors (4527425).

42203413303 is an equidigital number, since it uses as much as digits as its factorization.

42203413303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4527424.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 42203413303 its reverse (30331430224), we get a palindrome (72534843527).

The spelling of 42203413303 in words is "forty-two billion, two hundred three million, four hundred thirteen thousand, three hundred three".

Divisors: 1 9341 4518083 42203413303