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42210212433 = 314070070811
BaseRepresentation
bin100111010011111011…
…001011101001010001
311000221200221221222020
4213103323023221101
51142421303244213
631220251202053
73023002612554
oct472373135121
9130850857866
1042210212433
11169a0623394
128220146329
133c98c4b37c
142085d4669b
151170a6e923
hex9d3ecba51

42210212433 has 4 divisors (see below), whose sum is σ = 56280283248. Its totient is φ = 28140141620.

The previous prime is 42210212431. The next prime is 42210212437. The reversal of 42210212433 is 33421201224.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 42210212433 - 21 = 42210212431 is a prime.

It is not an unprimeable number, because it can be changed into a prime (42210212431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7035035403 + ... + 7035035408.

It is an arithmetic number, because the mean of its divisors is an integer number (14070070812).

Almost surely, 242210212433 is an apocalyptic number.

It is an amenable number.

42210212433 is a deficient number, since it is larger than the sum of its proper divisors (14070070815).

42210212433 is a wasteful number, since it uses less digits than its factorization.

42210212433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14070070814.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 42210212433 its reverse (33421201224), we get a palindrome (75631413657).

The spelling of 42210212433 in words is "forty-two billion, two hundred ten million, two hundred twelve thousand, four hundred thirty-three".

Divisors: 1 3 14070070811 42210212433