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42213012370433 is a prime number
BaseRepresentation
bin10011001100100011110111…
…00110110111010000000001
312112110112011102010110021122
421212101323212313100001
521013104222131323213
6225440220135402025
711614534540604612
oct1146217346672001
9175415142113248
1042213012370433
11124a548aaa0603
1248991b8523315
131a72892c61478
14a5d1992b5c09
154d30cd715d08
hex26647b9b7401

42213012370433 has 2 divisors, whose sum is σ = 42213012370434. Its totient is φ = 42213012370432.

The previous prime is 42213012370423. The next prime is 42213012370447. The reversal of 42213012370433 is 33407321031224.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36086535940849 + 6126476429584 = 6007207^2 + 2475172^2 .

It is a cyclic number.

It is not a de Polignac number, because 42213012370433 - 226 = 42212945261569 is a prime.

It is a super-2 number, since 2×422130123704332 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 42213012370393 and 42213012370402.

It is not a weakly prime, because it can be changed into another prime (42213012370423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 21106506185216 + 21106506185217.

It is an arithmetic number, because the mean of its divisors is an integer number (21106506185217).

Almost surely, 242213012370433 is an apocalyptic number.

It is an amenable number.

42213012370433 is a deficient number, since it is larger than the sum of its proper divisors (1).

42213012370433 is an equidigital number, since it uses as much as digits as its factorization.

42213012370433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72576, while the sum is 35.

The spelling of 42213012370433 in words is "forty-two trillion, two hundred thirteen billion, twelve million, three hundred seventy thousand, four hundred thirty-three".