Base | Representation |
---|---|
bin | 111101011101000101110… |
… | …101001101110111100011 |
3 | 112221201121210200011022022 |
4 | 331131011311031313203 |
5 | 1023142424323232212 |
6 | 12552024312532055 |
7 | 614052650242226 |
oct | 75350565156743 |
9 | 15851553604268 |
10 | 4223124430307 |
11 | 138902070a5a2 |
12 | 5825779b102b |
13 | 248314bc2363 |
14 | 10858665d5bd |
15 | 74cbe61c772 |
hex | 3d745d4dde3 |
4223124430307 has 2 divisors, whose sum is σ = 4223124430308. Its totient is φ = 4223124430306.
The previous prime is 4223124430277. The next prime is 4223124430319. The reversal of 4223124430307 is 7030344213224.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4223124430307 - 26 = 4223124430243 is a prime.
It is a super-3 number, since 3×42231244303073 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (4223124430337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2111562215153 + 2111562215154.
It is an arithmetic number, because the mean of its divisors is an integer number (2111562215154).
Almost surely, 24223124430307 is an apocalyptic number.
4223124430307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4223124430307 is an equidigital number, since it uses as much as digits as its factorization.
4223124430307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 4223124430307 in words is "four trillion, two hundred twenty-three billion, one hundred twenty-four million, four hundred thirty thousand, three hundred seven".
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