Base | Representation |
---|---|
bin | 110000000111010010000110… |
… | …1001001010111000001101011 |
3 | 2001111110210210102012202022201 |
4 | 1200032210031021113001223 |
5 | 420432412032212101441 |
6 | 4100033320302001031 |
7 | 155100105621553414 |
oct | 14016441511270153 |
9 | 2044423712182281 |
10 | 423213413003371 |
11 | 112937889542561 |
12 | 3b571717876177 |
13 | 1521bb13497723 |
14 | 76718d1dd680b |
15 | 33ddb434b0c31 |
hex | 180e90d25706b |
423213413003371 has 2 divisors, whose sum is σ = 423213413003372. Its totient is φ = 423213413003370.
The previous prime is 423213413003341. The next prime is 423213413003419. The reversal of 423213413003371 is 173300314312324.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 423213413003371 - 221 = 423213410906219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 423213413003371.
It is not a weakly prime, because it can be changed into another prime (423213413003341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 211606706501685 + 211606706501686.
It is an arithmetic number, because the mean of its divisors is an integer number (211606706501686).
Almost surely, 2423213413003371 is an apocalyptic number.
423213413003371 is a deficient number, since it is larger than the sum of its proper divisors (1).
423213413003371 is an equidigital number, since it uses as much as digits as its factorization.
423213413003371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108864, while the sum is 37.
Adding to 423213413003371 its reverse (173300314312324), we get a palindrome (596513727315695).
The spelling of 423213413003371 in words is "four hundred twenty-three trillion, two hundred thirteen billion, four hundred thirteen million, three thousand, three hundred seventy-one".
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