Base | Representation |
---|---|
bin | 111101100101101111111… |
… | …101111101100000010001 |
3 | 112222121121201101002022101 |
4 | 331211233331331200101 |
5 | 1023320444323101431 |
6 | 13000203021040401 |
7 | 614532226315261 |
oct | 75455775754021 |
9 | 15877551332271 |
10 | 4232421300241 |
11 | 1391a61537582 |
12 | 5843313b6101 |
13 | 249167015824 |
14 | 108bc92717a1 |
15 | 751658da961 |
hex | 3d96ff7d811 |
4232421300241 has 2 divisors, whose sum is σ = 4232421300242. Its totient is φ = 4232421300240.
The previous prime is 4232421300209. The next prime is 4232421300259. The reversal of 4232421300241 is 1420031242324.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 4102666454016 + 129754846225 = 2025504^2 + 360215^2 .
It is a cyclic number.
It is not a de Polignac number, because 4232421300241 - 25 = 4232421300209 is a prime.
It is not a weakly prime, because it can be changed into another prime (4232421300641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2116210650120 + 2116210650121.
It is an arithmetic number, because the mean of its divisors is an integer number (2116210650121).
Almost surely, 24232421300241 is an apocalyptic number.
It is an amenable number.
4232421300241 is a deficient number, since it is larger than the sum of its proper divisors (1).
4232421300241 is an equidigital number, since it uses as much as digits as its factorization.
4232421300241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 4232421300241 its reverse (1420031242324), we get a palindrome (5652452542565).
The spelling of 4232421300241 in words is "four trillion, two hundred thirty-two billion, four hundred twenty-one million, three hundred thousand, two hundred forty-one".
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